If an 9 – 5n find sum of 15th terms of an ap
Web27 apr. 2015 · To find the nth term in arithmetic sequence we use the formula a n = a + ( n − 1) d we already know the values of n and d and so I substitute: a 15 = a + ( 15 − 1) ( 2) a 15 = a + 28 I'm stuck here... sequences-and-series Share Cite Follow edited Apr 21, 2024 at 16:31 asked Apr 27, 2015 at 7:01 direprobs 492 3 9 23 Add a comment 3 Answers Web22 aug. 2024 · Answer: Sum of 15 terms in given A.P Sum of 15 terms in given A.P= -465 Step-by-step explanation: Given ---- (1) Now , substitute n=1 in equation (1), we get i) …
If an 9 – 5n find sum of 15th terms of an ap
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Web15 mrt. 2024 · Hence, the sum of the first 15 terms of an AP whose fifth and ninth terms are 26 and 42 respectively is given by 570. Note: Arithmetic Progression is a sequence … WebFrom bee8d8eea8fdd13c4a2dc822c1f415922fe26a8c Mon Sep 17 00:00:00 2001 From: zhanghx0905 [email protected]> Date: Mon, 6 Sep 2024 11:49:44 +0800 Subject: …
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WebSolution Given the general term is = 5-6n So, 1st term = 5 - 6 (1) = -1, 2nd term = 5 - 6 (2) = -7 3rd term = 5 - 6 (3) = -13 Hence the AP would be -1,-7,-13,-19,...... an. with the first … Web16 okt. 2024 · Best answer Sn = 3n2 + 5n Taking n = 1, we get S1 = 3 (1)2 + 5 (1) ⇒ S1 = 3 + 5 ⇒ S1 = 8 ⇒ a1 = 8 Taking n = 2, we get S2 = 3 (2)2 + 5 (2) ⇒ S2 = 12 + 10 ⇒ S2 = 22 ∴ a2 = S2 – S1 = 22 – 8 = 14 Taking n = 3, we get S3 = 3 (3)2 + 5 (3) ⇒ S3 = 27 + 15 ⇒ S3 = 42 ∴ a3 = S3 – S2 = 42 – 22 = 20 So, a = 8, d = a2 – a1 = 14 – 8 = 6
WebThe sum of n terms of an AP is 3n 2 + 5n and then which term of AP is 164. Solution let the term be m S = 3n 2 + 5n S 1 = a 1 = 3 + 5 = 8 S 2 = a 1 + a 2 = 12 + 10 = 22 ⇒ a 2 = S 2 - S 1 = 22 - 8 = 14 S 3 = a 1 + a 2 + a 3 = 27 + 15 = 42 ⇒a 3 = S 3 - S 2 = 42 - 22 = 20 ∴ Given AP is 8,14,20,..... Thus a = 8 , d = 6 Given t m = 164. fiscal treasury check verificationWeb18 mrt. 2024 · Given an A.P. whose nth term is given by yn = 9 – 5n To find the sum of the n terms of the given A.P., using the formula, Sn = n(a + l) 2 n ( a + l) 2 Where, a = the first term l = the last term. Putting n = 1 in the given yn, we get a = 9 – 5 (1) = 9 – 5 = 4 For the last term (l), here n = 15 a15 = 9 – 5 (15) = -66 fiscal technologiesWeb28 dec. 2013 · Sum of 15 terms = (15/2) [1 + (-27)] = (15/2) × - 26 = -195 Recommend (1) Comment (0) person Syeda Answer. Given nth term of AP a n = 3 - 2n Put n = 1, we get … camping odalys le mas de champelWebIf the nth term of an A.P. is 9 — 5n, find the sum to first 15 terms. Given: an= 9 – 5n Taking n = 1, a1= 9 – 5(1) = 9 – 5 = 4 Taking n = 2, a2= 9 – 5(2) = 9 – 10 = -1 Taking n = … fiscal transactionsWebThe sum of first n terms of an A.P. is 5n2+3n. If its mth term is 168, find the value of m. Also, find the 20th terms of this A.P. Login Study Materials NCERT Solutions NCERT Solutions For Class 12 NCERT Solutions For Class 12 Physics NCERT Solutions For Class 12 Chemistry NCERT Solutions For Class 12 Biology NCERT Solutions For Class 12 Maths camping odalys languedoc roussillonWeb19 dec. 2024 · (iii) Sum of n terms of an AP is always quadratic in ‘n’ Example: S n = 2n 2 + 3n. Example: S n = n/4 (n + 1) we can find ‘d’ also from S n. d = 2 (coefficient of n 2) for eg. : 2n 2 + 3n, d = 2 (2) = 4 Verification: S n = 2n 2 + 3n at n = 1, S 1 = 2 + 3 = 5 = first term at n = 2, S 2 = 2 (2) 2 + 3 (2) = 8 + 6 = 14 ≠ second term fiscal trailsWeb21 feb. 2015 · If 9th term of an AP be zero, prove that 29th term is double of its 19th term. If the 5th term of an a.p is 13 and 17 th term is 49, find an and t13. Find the sum of n terms of series whose nth term is tn is 3n^2+2n. If the sum of m terms of an a p is same as the sum of its n terms show that the sum of m+n terms is zero fiscal unit process in nl